此文章來自奇摩知識+如有不便請留言告知
標題:
會考數學一問,急.......會考數學一問,急.......
發問:
請作解釋: 1.將110110111110001(2)轉成十六進制的數值。 A.7AE1(16) B.7CF2(16) C.DBE1(16) D.6DF1(16)
最佳解答:
110 110 111 110 001 (2) = 2^14 + 2^13 + 2^11 + 2^10 + 2^8 + 2^7 + 2^6 + 2^5 + 2^4 + 1 = 4*16^3 + 2*16^3 + 8*16^2 + 4*16^2 + 16^2 + 8*16 + 4*16 + 2*16 + 16 + 1 = 6*16^3 + 13*16^2 + 15*16 + 1 = 6DF1(16) (D) 2010-04-25 02:30:59 補充： 方法2 : 110 110 111 110 001 (2) = 2^14 + 2^13 + (2^11 + 2^10 + 2^8) + ( 2^7 + 2^6 + 2^5 + 2^4) + 1 = (2^2 + 2^1)(2^12) + (2^3 + 2^2 + 2^0)(2^8) + (2^3 + 2^2 + 2^1 + 2^0)(2^4) + 1 = (6)(16^3) + (13)(16^2) + (15)(16^1) + 1 = 6DF1(16) (D)
其他解答:
Actually, you can look at this in this way . Since 110110111110001(2) is in binary, right? If you want to change it to 十六進制, what you have to do is: 1.) separate it into 4 numbers a group 110 1101 1111 0001 (1) (2) (3) (4) Because the first group (1) only got 3 numbers, we will give it one more zero in the beginning, so it will become 0110 1101 1111 0001 You should have learned the conversion: Binary(2 進制) Hex (十六進制) 0001 1 0010 2 0011 3 0100 4 0101 5 0110 6 0111 7 1000 8 1001 9 1010 A 1011 B 1100 C 1101 D 1110 E 1111 F So right now, we will convert the 4 groups of numbers 0110 1101 1111 0001 0110 -> 6 1101 -> D 1111 -> F 0001 -> 1 So the answer is D. If you got anything you don't understand, tell me. Wish 會考 successful ! ^^ 2010-04-25 03:37:54 補充： I hope The conversion table is not too messy for you to understand: Binary(2 進制) Hex (十六進制) 0001 1 0010 2 ...... etc 1010 A 1011 B ........ etc It means 0001(2) is 1 in 十六進制 1010(2) is A in 十六進制6CC7293C79127CE5
留言列表
